Comments for Afiata.com

Comment on Project for 20 or 40 watt fluorescent tubes – Inverter by admin

admin — Tue, 09 Mar 2010 16:25:35 +0000

240V inverter to build a replacement for fluorescent 30W, 40W circuit will work normally on 30W lamp because the difference is not too much

Comment on Project for 20 or 40 watt fluorescent tubes – Inverter by Riaan

Riaan — Mon, 08 Mar 2010 08:43:44 +0000

Hey, nice article!

I’m not an expert in these matters at all. I need to build a replacement 240V inverter for a 30W fluorescent tube. Will this 40W circuit work, or will it drive the 30W lamp too hard? (It’s one of those round jobs used in magnifying lamps, so it’s expensive to replace.)

Thanks!
Riaan

Comment on Electronic circuit diagram Low distortion audio amplifier Using LA4282 by erectile dysfunction

erectile dysfunction — Fri, 05 Mar 2010 19:52:07 +0000

Are you a professional journalist? You write very well.

Comment on circuit diagram? by kioyi l

kioyi l — Fri, 05 Mar 2010 17:03:38 +0000

do you mean:
—–5—–||28———–
|
|—–4——-|
|——12—-|——6—–| ?

1)R= 4*12/(4+12)=3ohm
Rdown=3+6=9ohm
Rup=5ohm
Rtotal=5+9=14ohm
Ctotal=U/Rtotal=28/14=2A
2)C(resistor 5ohm)=C(resistor 6hom)=Ctotal=2A
U(resistor 4ohm and 12ohm)=Ctotal*R=2*3=6V
C(resistor 4ohm)=U(resistor 4ohm and 12ohm)/4ohm=6/4=1.5A
C(resistor 12 ohm)=6/12=0.5A
4)q=I*t=2*60=120c
5)U(resistor 4ohm and 12ohm)=U(resistor 12ohm)=6v (calculated above)
W=UCt=6*0.5*60=180J=Q(heat created)
6)P=U*C=28*2=56watts

Comment on Printed Circuit Board Design and Method by Master-BilK

Master-BilK — Thu, 04 Mar 2010 21:51:26 +0000